Respuesta :
Answer: 16
Step-by-step explanation:
Tickets for a play were $2 for a child and $4 for an adult.
Tickets price for a child= $2
Tickets price for an adult= $4
One adult brought 4 children. This will give a price of:
(1×4) + (2×4) = 4+8 = $12
The remaining adults brought 2 children each.
Let the remaining adults be y. Each adult will spend:
4+(2×2) = 4+4 = $8
Since there are y adults, it will give 8×y = 8y.
8y + 12 = 60
8y = 60-12
8y = 48
y = 48/8 = 6
The remaining adults are 6. Since we had one adult earlier, total adults will be 7.
To get the number of children that went to the play will be:
(P × number of children) + (price× number of adults) = $60
= (2 × children) + (4 × 7) = $60
= (2 × children) + $28 = $60
= (2 × children) = $60 - $28
= (2 × children) = $32
Children= 32/2
Children= 16
There are 16 children at the play.
Answer:
16 children attended the play
Step-by-step explanation:
Since one adult brought four children. The cost of their tickets should be:
($4×1) + ($2×1)
= 4+8
= $12
Since the remaining adults brought 2 children each, it means that each of the remaining adults will pay the cost of three tickets (1 for themselves and 2 for their children) which is:
($4×1) + ($2×2) = $4 + $4 = $8.
Since total cost of tickets for adults and children = $60, we will subtract $12 from $60 in order to know the cost of the tickets for the remaining adults and their children.
$60 - $12 = $48
Each of the remaining adults paid $8 as ticket cost for themselves and their kids. If the adults that brought only 2 kids paid a combined $48, then the number of adults that brought 2 kids each
= $48/$8
= 6 adults.
If each of these 6 adults brought 2 kids each, then the number of children that they brought = 2 × 6 = 12
We now add this to the four children of the first adult
12 + 4 = 16
Therefore the number of children that attended the play = 16
