Answer:
The voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.
Explanation:
Given;
Resistance, R₁ = 50Ω
Resistance, R₂ = 75Ω
Total resistance, R = (R₁R₂)/(R₁ + R₂)
Total resistance, R = (50 x 75)/(125)
Total resistance, R = 30 Ω
According to ohms law, sum of current in a parallel circuit is given as
I = I₁ + I₂
[tex]I = \frac{V}{R_1} + \frac{V}{R_2}[/tex]
Voltage across each resistor is the same
[tex]1.6 = \frac{V}{R_2}[/tex]
V = 1.6 x R₂
V = 1.6 x 75
V = 120 V
Therefore, the voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.
This voltage is also the same for 50 ohms resistance but the current will be 2.4 A.
Answer:
120 volts
Explanation:
Since the two resistances are connected in parallel across the voltage source, the effective resistance of the circuit can be obtained by using the formula.
[tex]\frac{1}{R_{eq}}=\frac{1}{R_{1}}+ \frac{1}{R_{2}}[/tex]
given that [tex]R_{1} and R_{2}[/tex] are 50 and 75 ohms respectively, we have the equivalent resistance as:
[tex]\frac{1}{R_{eq}}=\frac{1}{50}+ \frac{1}{75}=\frac{1}{30}[/tex]
hence,
[tex]R_{eq}= 30\Omega[/tex]
From Ohm's law, voltage = current X resistance.
given that the current through the 75 ohm resistor is 1.6 A
[tex]V= I\times R[/tex]
[tex]V= 1.6 \times 75\Omega[/tex]
voltage = 120 Volts.
Because the resistors are connected in parallel, it means that they are connected to the same voltage source.
Hence, the voltage source for the 75 Ohm resistance = 120 volts. This is same for the 50 Ohm resistor.
