A ranch experienced growth of its gopher population at a 1.5% annual rate, compounded continuously. At the end of a 3 year period, the population had reached a size of 78 gophers. How many gophers were on the ranch at the beginning of the 3 years according to the exponential growth function? Round your answer up to the nearest whole number, and do not include units.

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Answer:

75 gophers (about)

Step-by-step explanation:

We will use continuous compounding interest formula:

[tex]P(t)=P_0e^{rt}[/tex]

Where

P(t) is final value (at time t)

P_0 is initial value

r is the compounding rate

t is the time period

Given:

P(t) = 78

r is 1.5% or 1.5/100 = 0.015

t is 3

We solve for P_0, what we want, using algebra as shown below:

[tex]P(t)=P_0e^{rt}\\78=P_0e^{(0.015)(3)}\\78=P_0e^{0.045}\\\frac{78}{P_0}=e^{0.045}\\\frac{78}{P_0}=1.0460\\P_0=74.57[/tex]

So, the initial population was 75 gophers.

Answer:

75 gophers

Step-by-step explanation: