Answer:
[tex]\$456[/tex]
Step-by-step explanation:
The correct question is
Mr. Hopkins is building a sandbox for his children. It would cost $228 for the sand if he builds a sandbox with dimensions 9 ft by 6 ft. If Mr. Hopkins decides to increase the size to 13 1/2 ft by 8 ft but keep the same depth of sand, how much would the sand cost
step 1
Find the unit rate of the cost per square foot
Divide the total cost by the area
[tex]\frac{228}{9*6}=\$\frac{38}{9}\ per\ square\ foot[/tex]
step 2
Find the area of the increased sandbox
we have
[tex]L=13\frac{1}{2}=13.5\ ft[/tex]
[tex]W=8\ ft[/tex]
The area is equal to
[tex]A=(13.5)(8)=108\ ft^2[/tex]
step 3
Find the cost of the new sandbox
Multiply the area by the cost per square foot
[tex]108(\frac{38}{9})=\$456[/tex]
