[tex](\frac{-5}{7})^8 \times (\frac{-5}{7})^9 = (\frac{-5}{7})^{17}[/tex]
Solution:
Given that,
We have to simplify the expression
[tex](\frac{-5}{7})^8 \times (\frac{-5}{7})^9[/tex]
When multiplying two powers that have the same base, we can add the exponents
Which means,
[tex]a^m \times a^n = a^{m+n}[/tex]
Therefore,
[tex](\frac{-5}{7})^8 \times (\frac{-5}{7})^9 = (\frac{-5}{7})^{8+9} \\\\(\frac{-5}{7})^8 \times (\frac{-5}{7})^9 = (\frac{-5}{7})^{17}[/tex]
Thus the given expression is written as answer with single power
