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You are conducting a dihybrid cross. You mate a homozygous-dominant-smooth homozygous-recessive-green pea plant (SSyy) with a heterozygous-smooth homozygous-dominant-yellow pea plant (SsYY). What is the likelihood of obtaining an offspring with the following genotype: SSYy? Note: SS and Ss will result in the smooth phenotype; ss will result in the wrinkled phenotype; YY and Yy will result in the yellow phenotype; yy will result in the green phenotype. Hint: you are crossing the following: SSyy X SsYY. What is the likelihood of getting the following: SSYy?

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ShyzaSling

Answer:

8/16 or 50% is the likelihood of getting SSYy.

Explanation:

To predict the outcome of the occurrence of SSYy, let's make a punnet square:

            SY         SY        sY         sY

Sy    SSYy      SSYy     SsYy       SsYy

Sy    SSYy     SSYy     SsYy         SsYy

Sy   SSYy     SSYy      SsYy        SsYy

Sy   SSYy     SSYy     SsYy        SsYy

8/16 of the plants will have a chance of having the genotype: SSYy  This means that the there will be a 50% chance that the genotype of the offspring will be SSYy.

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