Answer:
1.12 g of oxygen.
Explanation:
First step is to determine the decomposition reaction:
Ammonium perchlorate → NH₄ClO₄
2NH₄ClO₄ (s) → N₂(g) + Cl₂(g) + 2O₂(g) + 4H₂O(g)
We define the moles of the reactant:
4.1 g . /117.45 g/mol = 0.0349 moles
As ratio is 2:2, If I use 0.0349 moles of perchlorate I would produce the same amount of moles of oxygen.
0.0349 mol of O₂ are produced by the reaction
We convert to mass: 0.0349 mol . 32 g /1mol = 1.12 g