Answer:
see the explanation
Step-by-step explanation:
see the attached figure to better understand the problem
we have that
OA+OB=radii of circle O
Point P is equidistant from radii OA and OB ----> given problem
so
PA=PB
OP is a common side
Triangle OAP is congruent to Triangle OBP by SSS Postulate Theorem
Remember that
If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent
That means
[tex]m\angle POA=m\angle POB[/tex]
therefore
The radius from the point (PO) bisects the angle formed by the two given radii (angle ∠AOB)
