The rate of effusion of gas B is 728.32 m/s
Explanation:
Given:
Mass of A, m₁ = 46 g/mol
Rate of effusion of A, R₁ = 515 m/s
Mass of B, m₂ = 92 g/mol
Rate of effusion of B, R₂ = ?
We know:
[tex]\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} }[/tex]
Substituting the value we get:
[tex]\frac{515}{R_2} = \sqrt{\frac{92}{46} } \\\\\frac{515}{R_2} = \sqrt{2} \\\\R_2 = \frac{515}{\sqrt{2} } \\\\R_2 = 728.32 m/s[/tex]
Therefore, the rate of effusion of gas B is 728.32 m/s
