The required angle of the projectile motion having range 20 m and initial velocity 15 m is 30.29°
Range of the projectile motion:
The formula for finding projectile motion is given by
Range R = [tex]\frac{v^2sin2\theta}{g}[/tex]
where v is the initial velocity and g is acceleration and [tex]\theta[/tex] is the projectile angle of the object
How to calculate angle ?
If we have given range and initial velocity with acceleration then by substituting above range formula we can find angle of the projectile
Here we have given that
R = 20 m
v = 15 m/s
g = 9.8 m/s^2
Therefore
[tex]20=\frac{15^2sin2\theta}{9.8}[/tex]
[tex]sin2\theta=\frac{20(9.8)}{225}[/tex]
[tex]\theta[/tex] = 30.29
This is the required angle of the projectile
Learn more about range of projectile motion here-
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