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A portable x-ray unit has a step-up transformer. The 120 V input is transformed to the 100 kV output needed by the x-ray tube. The primary has 73 loops and draws a current of 14.1 A when in use. What is the number of loops in the secondary

Respuesta :

Answer:

60833 loops

Explanation:

Given parameters:

Input voltage  = 120V

Output voltage  = 100kV

Primary loops  = 73 loops

Current = 14.1A

Unknown:

Number of loops in the secondary coil  = ?

Solution:

A step up transformer of this nature increases the output voltage. Here, the voltage is raised on the output side.

One thing about a transformer is that the output and input power are always the same.

To find the number of loops in the secondary coil;

             [tex]\frac{N_{p} }{N_{s} } = \frac{V_{p} }{V_{s} }[/tex]

Where N is the number of loops and V is the voltage

            s and p are the secondary and primary parts

Note: 100kV  = 100000V

 Now input the parameters;

          [tex]\frac{73}{N_{s} } = \frac{120}{100000}[/tex]

     120N[tex]_{s}[/tex]   = 73 x 100000

            N[tex]_{s}[/tex]  = 60833 loops