To solve this problem we will apply the concepts related to the double slit experiment. Here we test a relationship between the sine of the deviation angle and the distance between slit versus wavelength and the bright fringe order. Mathematically it can be described as,
[tex]dsin\theta = m\lambda[/tex]
Here,
d = Distance between slits
m = Any integer which represent the order number or the number of repetition of the spectrum
[tex]\lambda[/tex] = Wavelength
[tex]\theta[/tex] = Angular deviation
Replacing with our values we have,
[tex](6.93*10^{-6}) sin\theta = (3)(491*10^{-9})[/tex]
[tex]\theta = sin^{-1} (\frac{(3)(491*10^{-9}}{6.93*10^{-6}) })[/tex]
Part A)
[tex]\theta = 0.2141rad[/tex]
PART B)
[tex]\theta = 0.2141rad(\frac{360\°}{2\pi rad})[/tex]
[tex]\theta = 12.27\°[/tex]
