Answer:
The exponential form is 49 to the power of one-half equals 7 ⇒ 4th answer
Step-by-step explanation:
The exponential equation of [tex]log_{b}(m)=n[/tex] is [tex]b^{n}=m[/tex] , where b is the base, n is the exponent of b and m is the value of [tex]b^{n}[/tex]
Ex: If [tex]log_{3}(81)=4[/tex] , that means b = 3 , n = 4 and m = 81, then its exponential form is [tex]3^{4}=81[/tex]
Now let us solve the question
∵ The equation is [tex]log_{49}(7)=\frac{1}{2}[/tex]
∴ The base is 49
∴ The exponent is [tex]\frac{1}{2}[/tex]
∴ The answer is 7
- Substitute them in the form of the exponential form
∴ The exponential form is [tex](49)^{\frac{1}{2}}=7[/tex]
The exponential form is 49 to the power of one-half equals 7
