Answer:
601.8mL
Explanation:
First, we'll begin by obtaining an equation connecting volume and number of mole together. This is illustrated below:
From the ideal gas equation:
PV = nRT
Divide both side by P
V = nRT/P
Now divide both side by n
V/n = RT/P
Under the same conditions simply means temperature(T), pressure (P) and the gas constant (R) are all constant i.e
RT/P => constant
Therefore, the above equation can be written as:
V1/n1 = V2/n2
Now we can solve for the final volume otherwise known as the new volume as follow:
Data obtained from the question include:
n1 (initial mole) = 0.214 mol
V1 (initial volume) = 343.4 mL
n2 (final mole) = 0.375 mol
V2 (final volume) =?
Applying the the equation V1/n1 = V2/n2, the final volume is obtain as illustrated below:
V1/n1 = V2/n2
343.4/0.214 = V2/0.375
Cross multiply to express in linear form
0.214 x V2 = 343.4 x 0.375
Divide both side by 0.214
V2 = (343.4 x 0.375)/0.214
V2 = 601.8mL
Therefore, 0.375 mol of argon gas will occupy 601.8mL under the same condition.
