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Consider the graph that represents the following quadratic equation.
y=-1/3(x+2)^2+5
--the graph opens:
-downward
-upward
--the vertex of the graph is:
-(2,5)
-(-2,-5)
-(-2,5)
--the axis of symmetry of the graph is:
-x=2
-x=-2

Respuesta :

calculista

Answer:

Part 1) The graphs open downward

Part 2) The vertex is the point (-2,5)

Part 3) The axis of symmetry is x=-2

Step-by-step explanation:

step 1

we have

[tex]y=-\frac{1}{3}(x+2)^2+5[/tex]

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex is a maximum

step 2

The quadratic equation is written in vertex form

[tex]y=a(x-h)^2+k[/tex]

where

(h,k) is the vertex

so

In this problem

The vertex is the point (-2,5)

step 3

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

The x-coordinate of the vertex is -2

therefore

The axis of symmetry is x=-2

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