Two candles of equal height start to burn simultaneously. One of the candles is thicker than the other one and burns out in 4 hours, while the thinner one burns out in 2 hours. Both of the candles are extinguished after some time, and the remaining height of the thicker candle is now 3 times as long as the thinner one. How many minutes were the candles burning for?

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917006450984help 917006450984help · Answer 1 · 2020-04-03T14:35:26+02:00

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maheshpatelvVT maheshpatelvVT · Answer 2 · 2022-07-21T13:01:48+02:00

For 96 minutes the candles were burning if two candles of equal height start to burn simultaneously.

It is defined as the change in values of a dependent variable with respect to the independent variables.

W have:

Rate of burning for thicker = h/4

Rate of burning for thinner= h/2

remaining part = h - ht/4

remaining part = h - ht/2

h - ht/4 = 3(h - ht/2)

After solving for t:

t = 8/5 hours

or

t = 96 minutes

Thus, for 96 minutes the candles were burning if two candles of equal height start to burn simultaneously.

Learn more about the rate of change here:

brainly.com/question/12786410

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