Respuesta :
Answer:
[tex]P(t)=185,000*0.9444^{\frac{t}{2}}[/tex]
Step-by-step explanation:
This is a exponential modelling problem.
The population looses 1/18th of it every 2 months.
That in decimal is:
1/18 = 0.0556
in percentage, 5.56% lost every 2 months
So, remaining:
100 - 5.56 = 94.44%
in decimal that is
0.9444 (to 4 decimal)
Now, the equation modeled would be in the form:
[tex]P(t)=C*I^{\frac{t}{n}}[/tex]
Where
C is the initial amount (185,000)
I is the factor that we decrease by (we found to be 0.9444)
n is the months it decreases by that factor (so, n = 2 cuz every 2 months)
Now we substitute and write the exponential model equation:
[tex]P(t)=C*I^{\frac{t}{n}}\\P(t)=185,000*0.9444^{\frac{t}{2}}[/tex]