Answer:
[tex]x=\frac{1}{36} \, \,and\,\, x=-\frac{1}{36}[/tex]
Step-by-step explanation:
To find at which values of the argument the function renders 144, we need to solve for "x" in the equation when y is 144:
[tex]y=\frac{1}{9\,x^2}\\144=\frac{1}{9\,x^2}\\144\,x^2=\frac{1}{9} \\x^2=\frac{1}{9\,(144)} \\x^2=\frac{1}{1296} \\x=+/-\sqrt{\frac{1}{1296} } \\x=+/-\frac{1}{36}[/tex]
Therefore there are two solutions: one is 1/36 and the other one is its opposite; -1/36
