Answer:
11.427L
Explanation:
From the ideal gas law,
PV=nRT
Where;
P=pressure of the gas
V=volume of the gas occupied by the container
n=number of moles of the gas
R=the ideal gas constant=0.0821atmL/mol/K
Given
P=4.258atm
V=?
n=2.0801mol
T=284.92K
From the equation
PV=nRT,
We will make V subject of formula
V=nRT/P
Let's now substitute the values
V=(2.0801×0.0821×284.92)/4.258
V=11.427L
Therefore, the volume of the container is 11.427L
Answer:
11.41L
Explanation:
Data obtained from the question include:
n (number of mole of Br2) = 2.0801 mol
P (pressure) = 4.258 atm
T (temperature) = 284.92K
R (gas constant) = 0.082atm.L/Kmol
V (volume of the container) =?
Applying the ideal gas equation PV = nRT, the volume of the container can be obtained as follow:
PV = nRT
4.258 x V = 2.0801x0.082x284.92
Divide both side by 4.258
V = (2.0801x0.082x284.92)/4.258
V = 11.41L
Therefore, the volume of the container is 11.41L
