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Louisville, with a temperature of -1°C, is cooler than Boise, with a temperature of 5°C. Write an inequality for the relationship of these temperatures.

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kaancceylan

Answer:

The answer is X < Y

Step-by-step explanation:

Let Louisville's temperature be X and Boise's temperature be Y. According to the conditions given in the question where X is -1°C and Y is 5°C, the inequality should be written as X < Y.

I hope this answer helps.

batolisis

Answer:

y ≥ x

Y = temperature of Boise

X = temperature of Louisville

Step-by-step explanation:

Louisville temperature ( x ) = -1°c

Boise temperature ( y ) = 5°c

an inequality equation to represent this relationship will be  y ≥ x       this is because at any given time Louisville will always be cooler than Boise because its temperature is lower than Boise's temperature

An inequality  equation is an equation used to represent  two expressions or scenarios which are not equal to each other under given conditions

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