Answer:
The probability that two have ever boycotted goods for ethical reasons.= .2789
Step-by-step explanation:
Given - The survey found that 23% of the respondents have boycotted goods for ethical reasons .
The probability of success ( p) = 23[tex]\%[/tex] = 0.23
The probability of failure ( q) = 1 - p = .77
n = 6
Let X be the number of British citizens boycotted goods for ethical reasons.
The probability that two have ever boycotted goods for ethical reasons.
( Using Binomial distribution )
[tex]P(X = r )= \binom{n}{r}(p)^{r}(q)^{n - r}[/tex]
= [tex]\frac{6!}{(2!)(4!)}(.23)^{2}(.77)^{6 - 2}[/tex]
= [tex]\frac{6!}{(2!)(4!)}(.23)^{2}(.77)^{4}[/tex]
= [tex]15\times.0529\times.3515[/tex]
= .2789
