Answer:
Final angular speed of the wheel is given as
[tex]\omega = 31 rad/s[/tex]
Explanation:
Angle of revolution of the car wheel is
N = 3 turns
in one turn it will revolve by [tex]2\pi[/tex] angle
so we have
[tex]\theta = 3(2\pi)[/tex]
[tex]\theta = 6\pi[/tex]
now we can use kinematic to find the final speed
[tex]\omega^2 - \omega_0^2 = 2\alpha \theta[/tex]
so we have
[tex]\omega^2 - 10.8^2 = 2(22.4)(6\pi)[/tex]
[tex]\omega^2 = 10.8^2 + 844.5[/tex]
[tex]\omega = 31 rad/s[/tex]
