Melissa's solution is correct.
Explanation:
A(2, 8), B(2, 2), C(–4, 2), and D(–4, 8)
Length of AB = [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
[tex]=\sqrt{(2-8)^2+(2-2)^2} \\\\= \sqrt{36} \\\\= 6[/tex]
Length of BC = [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
= [tex]=\sqrt{(-4-2)^2+(2-2)^2} \\\\=\sqrt{36} \\\\= 6[/tex]
Area of rectangle = length X breadth
= 6 X 6
= 36 square units.
Therefore, Melissa's solution is correct.
