Answer:
d. 0.222 g
Explanation:
Given parameters:
volume of water = 71.9mL = 0.0719L
pressure = 1053.8kPa = 10.4atm
temperature = 738K
Unknown:
mass of water = ?
Solution:
To find the mass of water, we need to obtain the number of moles from the given parameters.
This can be done using the ideal gas law;
PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is the gas constant
T is the temperature
Input the parameters to find n;
10.4 x 0.0719 = n x 0.082 x 738
n = 0.012moles
Mass of water vapor = number of moles x molar mass
molar mass of H₂O = 2 + 16 = 18g/mol
Mass of water vapor = 0.012 x 18 = 0.22g