Answer:
So it looks like you only have two more questions there.
9.433.01 in ^2
10. To be determined...
Step-by-step explanation:
Here we have a bit of the same dilemma as the last problem. We are splitting the diagrams up into small triangles.
But, as before, we still don't have all the variables that are required.
This time, though, we will be making use of a 30-60-90 triangle. Although they are a bit more fiddly than a 45-45-90, they are much more useful.
The pentagon in number 9 is of especial interest. We know that we have a bottom length of 10, so that makes a perimeter of 50 in (5*10)
We also see that the apothem of the pentagon is the only thing remaining in our equation to be found.
To find the apothem:
a=[tex]10\sqrt{3}[/tex]=17.32
To find the area of the diagram:
17.32*10=173.20
173.21/2=86.60
86.60*5=433.01 in ^2
Sorry it took me so long.....can you do #10?
