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A bag contains 6 red marbles, 2 blue marbles, and 1 green marble. What is the
probability of choosing 2 marbles that are not green when 2 marbles are drawn
from the bag? (no replacement before choosing second marble)

Respuesta :

DeanR

We have 1 green and 8 non-green.  

We get a probability of 8/9 of a non-green for the first marble and a probably of 7/8 for the second being non green, so

p = (8/9)*(7/8) = 7/9

Answer: 7/9

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