Respuesta :
2.32 moles of carbon dioxide will be produced .
Step-by-step explanation:
Here we have , a sample of 70.0 g of carbon oxide was reacted completely with 32.0 g of oxygen. We need to find how many moles of carbon dioxide will be produced . Let's find out:
According to question , given equation of reaction is :
[tex]O_2+2CO[/tex] ⇒ [tex]2CO_2[/tex]
Now , Mass are given as :
[tex]O_2 = 16(2)=32g[/tex]
[tex]CO=12+16=28g[/tex]
[tex]CO_2=12+32=44g[/tex]
According to reaction , 32 g of [tex]O_2[/tex] + 2(28 g of CO ) gives 2( 44 g of [tex]CO_2[/tex] ) or ,
32 g of [tex]O_2[/tex] + 56 g of CO gives 88 g of [tex]CO_2[/tex]
So , 32 g of [tex]O_2[/tex] + 70 g of CO gives :
⇒ [tex]70+32=102g[/tex]
Moles of [tex]CO_2[/tex] = [tex]\frac{102}{44 }[/tex]
Moles of [tex]CO_2[/tex] = [tex]2.32[/tex]
Therefore , 2.32 moles of carbon dioxide will be produced .
