Answer:
591.7°C
Explanation:
Data obtained from the question include:
T1 (initial temperature) = 27°C = 27 + 273 = 300K
P1 (initial pressure) = 0.850 atm
P2 (final pressure) = 2.45 atm
T2 (final temperature) =?
Using the equation P1/T1 = P2/T2,
The final temperature i.e the temperature at which the glass vessel can be shattered can be obtained as follow:
P1/T1 = P2/T2
0.850/300 = 2.45/T2
Cross multiply to express in linear form as shown below:
0.850 x T2 = 300 x 2.45
Divide both side by 0.850
T2 = (300 x 2.45) /0.850
T2 = 864.7K
Now let us convert 864.7K to celsius temperature. This is illustrated below:
°C = K - 273
°C = 864.7 - 273
°C = 591.7°C
Therefore, the temperature at which the glass vessel will shatter is 591.7°C
Answer:
The temperature is 591.55 °C (or 864.7K)
Explanation:
Step 1: data given
Temperature = 27 °C = 300 K
The pressure = 0.850 atm
The vessel can withstand a pressure of 2.45 atm
Step 2: Guy-Lussac's law
Using Guy-Lussac's law (P1/T1) = (P2/T2) where temperature is measured in Kelvin (K = ºC +273), we can solve this problem.
P1/T1 = P2/T2
⇒with P1 = the initial pressure of the gas = 0.850 atm
⇒with T1 = the initial temperature = 300K
⇒with P2 = the max pressure the vessel ca nwithstand = 2.45 atm
⇒with T2 = the new temperature = TO BE DETERMINED
T2 = (P2*T1)/P1
T2 = (2.45 atm * 300K)/0.850 atm
T2 = 864.7 K = 591.55 °C
The temperature is 591.55 °C (or 864.7K)
