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What is the volume of 4.9 mol of an ideal gas
at a pressure of 3 atm and a temperature of
0◦ C? 1 liter = 0.001 m^3
and 1 atm = 101300 Pascals. Answer in units of L.

Respuesta :

Answer:

Volume of the gas is given as

[tex]V = 0.11 m^3[/tex]

Explanation:

As we know by ideal gas equation

[tex]PV = nRT[/tex]

here we know that

n = 4.9 moles

R = 8.314 J/ mol K

T = 0 degree = 273 K

P = 1 atm = 101300 Pa

now we have

[tex]101300 V = 4.9(8.314)(273)[/tex]

[tex]V = 0.11 m^3[/tex]

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