The other solution is x = 0.
Step-by-step explanation:
Let the value of (?) is C.
It the given equation is [tex](6x+4)^{2}[/tex] = C .
It can be written as [tex](6x+4)^{2} - C[/tex]
Since x = [tex]\frac{-4}{3}[/tex] is the solution of the given equation, therefore will satisfies the given equation.
Put x = [tex]\frac{-4}{3}[/tex]
[tex]( 6 (\frac{-4}{3}) + 4 )^{2} - C = 0[/tex]
[tex]( -8 + 4 )^{2}[/tex] - C = 0
[tex]- 4^{2}[/tex] - C = 0
C = 16
The given equation become
[tex](6x+4)^{2} + 16 = 0[/tex]
[tex]6x + 4 = 4[/tex]
6x = 0
[tex]6x + 4 = -4[/tex]
x = [tex]\frac{-4}{3}[/tex]
The other solution is x = 0.
