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*WILL GIVE BRAINLIEST* How many liters of 4.0 M NaOH solution will react with 1.8 mol H2SO4? (Remember to balance the equation.) H2SO4 + NaOH → Na2SO4 + H2O
A. 0.90 L
B. 1.0 L
C. 1.1 L
D. 2.1 L

Respuesta :

llamalover888

Answer:

Hello~

Llamalover here!

A. 0.90 L.

Explanation:

NaOH solution will react with H₂SO₄ according to the balanced reaction:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.

1.0 mole of H₂SO₄ reacts with 2.0 moles of NaOH.

For NaOH to react completely with H₂SO₄, the no. of millimoles should be equal.

∴ (MV) NaOH = (xMV) H₂SO₄.

x for H₂SO₄ = 2, due to having to reproducible H⁺ ions.

∴ V of NaOH = (xMV) H₂SO₄/ M of NaOH = 2(0.6 L)(3.0 M)/(4.0 M) = 0.90 L.

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Hope this helps!

pstnonsonjoku

The correct answer is A: 0.90 L

The balanced reaction equation including states of matter is;

H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)

Now, we can see from this reaction equation that the mole ratio of NaOH to H2SO4 is 2:1

Number of moles of H2SO4 reacted = 1.8 moles

Hence;

2 moles of NaOH reacts with 1 mole of H2SO4

x moles of NaOH reacts with 1.8 moles of H2SO4

x = 2 * 1.8/1 = 3.6 moles of NaOH

Recall that;

number of moles = concentration * volume

volume = number of moles/concentration

Volume of NaOH  is obtained from;

volume = 3.6 moles/ 4.0 M

volume =  0.90 L

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