Respuesta :
Length is 8 m and width is 4 m.
Step-by-step explanation:
Given,
The area of the rectangular table = 35 sq m
Sum of its dimensions = 12 m
To find the length and width of the table.
Let, the length and width of the table is l and b respectively.
As per the problem,
lb = 35 and l+b = 12
Formula
(a-b)² = (a+b)²-4ab
Now,
(l-b)² = (l+b)²-4lb
= (12)²-4×35 = 4
so, (l-b) = 2
Now we will solve l+b = 12 and l-b = 4
By adding we get,
l+b+l-b = 12+4
or, 2l = 16
or, l = 8
And b= 12-l = 12-8 = 4
Hence,
Length is 8 m and width is 4 m.
The dimensions are 5 inches and 7 inches.
Let, length = x and width = y.
According to the question:
Area = xy = 35
x + y = 12
or, y = 12 - x.
Plug y = 12 - x in xy = 35.
[tex]xy = 35\\ x(12-x) = 35\\ 12x-x^2=35\\ x^2-12x+35=0\\ (x-5)(x-7)=0\\ x=5,7[/tex]
Hence the dimensions are 5 inches and 7 inches.
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