Respuesta :
JDK-right triangle. JD=13, DK=3
By the Pythagorean theorem
[tex]13^2+3^2=JK^2\\JK=\sqrt{169+9} \\JK=\sqrt{178} \\[/tex]
JK≈13,34
Answer: the distance is 13 units
P.S. Hello from Russia
The distance between two points J and K is 13 unit (approx)
Step-by-step explanation:
Given,
Two points are J(3,0) and k(6,-13).
To find the distance between J and K.
Formula
The distance between two points ([tex]x_{1} ,y_{1}[/tex]) and ([tex]x_{2} ,y_{2}[/tex]) is [tex]\sqrt{(x_{2}-x_{1} ) ^{2}+(y_{2}-y_{1} ) ^{2} }[/tex]
Now,
Putting, [tex]x_{1} = 3, y_{1}=0, x_{2}=6, y_{2}=-13[/tex] we get,
JK = [tex]\sqrt{(6-3)^{2} +(-13-0)^{2} }[/tex]
= [tex]\sqrt{178}[/tex] unit = 13.34 unit (approx)