Respuesta :
Answer:
1.20
Step-by-step explanation:
Let mean be represented by M and standard deviation by d. The score will be x and sample number of games be n
To get the test statistic, t for Fernanda's test, we use the formula
[tex]t=\frac {M-x}{\frac{s}{\sqrt n}}[/tex]
Substituting 156 for mean, M then 150 for score x and 30 for standard deviation while 36 for n then
[tex]t=\frac {156-150}{\frac{30}{\sqrt 36}}[/tex]
t=1.20 when put in two decimal place
The test statistic for Fernanda's test is 1.20.
Calculation of the test statistic;
Since She suspects that the league average score is greater than 150 per
game. She takes a random sample of 36 game scores from the league data. The scores in the sample have a mean of 156 and a standard deviation of 30.
So here the test statistic should be
[tex]= 156 - 150\div 30\div \sqrt{36}[/tex]
= 1.20
Hence, The test statistic for Fernanda's test is 1.20.
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