Given:
m∠APD = (7x + 1)°
m∠DPC = 90°
m∠CPB = (9x - 7)°
To find:
The measure of arc ACD.
Solution:
Sum of the adjacent angles in a straight line = 180°
m∠APD + m∠DPC + m∠CPB = 180°
7x° + 1° + 90° + 9x° - 7° = 180°
16x° + 84° = 180°
Subtract 84° from both sides.
16x° + 84° - 84° = 180° - 84°
16x° = 96°
Divide by 16° on both sides.
x = 6
m∠APB = 180°
m∠BPD = (9x - 7)° + 90°
= (9(6) - 7)° + 90°
= 47° + 90°
m∠BPD = 137°
m∠APD = m∠APB + m∠BPD
= 180° + 137°
= 317°
The measure of the central angle is congruent to the measure of the intercepted arc.
m(ar ACD) = m∠APD
m(ar ACD) = 317°
The arc measure of ACD is 317°.
