Respuesta :
Answer: The net ionic equation will be as follows.
[tex]CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)[/tex]
Explanation:
The chemical equation for the given reaction is as follows.
[tex]CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)[/tex]
We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.
[tex]CH_{3}COO^{-}(aq) + Na^{+}(aq) H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + Na^{+}(aq) + OH^{-}(aq)[/tex] Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.
[tex]CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)[/tex]
or, [tex]C_{2}H_{3}O^{-}_{2}(aq) + H_{2}O(l) \rightleftharpoons HC_{2}H_{3}O_{2}(aq) + OH^{-}(aq)[/tex]
Based on the nature of NaC₂H₃O₂, the net ionic equation is as follows:
- [tex]CH_{3}COO^{-} (aq) + H_{2}O < -- > CH_{3}COOH (aq) + OH^{-}[/tex]
What is the ionic equation of the dissociation of NaC₂H₃O₂?
NaC₂H₃O₂ is a weak acid and dissociates partially in water to produce sodium ions and acetate ions.
The ionic equation is given as follows.
- [tex]CH_{3}COO^{-} (aq) + Na^{+} + H_{2}O < -- > CH_{3}COOH (aq) + OH^{-} + Na^{+}[/tex]
The net ionic equation will not have the spectator ions present
In the dissociation of NaC₂H₃O₂, Na⁺ ions are spectator ions as they appear on both sides of the equation of the reaction.
Therefore, the net ionic equation will be as follows.
- [tex]CH_{3}COO^{-} (aq) + H_{2}O < -- > CH_{3}COOH (aq) + OH^{-}[/tex]
Learn more about net ionic equations at: https://brainly.com/question/25604204
