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. An open manometer is filled with mercury. The mercury level is 12mm higher on the side open to the atmosphere. What is the total pressure of the gas, in kPa, if the atmospheric pressure is 100.8 kPa?

Respuesta :

Answer:

102kPa

Explanation:

760mmHg = 101.325 kPa

12mmHg = x

Upon converting from mmHg to kPa we have;

x = ( 12 mm Hg x  101.325 kPa)  / 760mmHg

x = 1.599868421 kPa

Total pressure = 100.8 kPa + 1.599868421 kPa

Total pressure = 102kPa

Lanuel

The total pressure of the gas, in kPa is equal to 102.4 kPa.

Given the following data:

  • Atmospheric pressure = 100.8 kPa
  • Pressure (open side) = 12 mm Hg

To determine the total pressure of the gas, in kPa:

First of all, we would convert the value of the pressure in mm Hg to kPa.

Conversion:

760 mm Hg = 101.325 kPa

12 mm Hg = X kPa

Cross-multiplying, we have:

[tex]760X = 12\times 101.325\\\\760X = 1,215.9\\\\X=\frac{1215.9}{760}[/tex]

X = 1.60 kPa

Now, we can calculate the total pressure by using this formula:

[tex]Total\;pressure = Atmospheric \;pressure + Pressure (side)\\\\Total\;pressure = 100.8 + 1.60[/tex]

Total pressure = 102.4 kPa

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