sanchezkim260
contestada

A 970 kg car starts from rest on a horizontal roadway and accelerates eastward
for 5 s when it reaches a speed of 25 m/s. What is the average force exerted on
the car during this time? (Hint: Find acceleration of the car, then use the equation
F=ma.)

Respuesta :

olatunbosunadeoke

Answer: 4850N

Explanation:

Mass of car = 970 kg

Time = 5 s

Speed = 25 m/s

Average force exerted on the car = ?

Recall that Force is the product of the mass of an object and the acceleration by which it moves

i.e Force = mass x acceleration

(Since, acceleration is the rate of change of velocity or speed per unit time)

i.e Acceleration = Speed / Time

Acc = 25m/s / 5s

Acc = 5m/s^2

Average force = mass x acceleration

Avg force = 970 kg x 5m/s^2

= 4850N

Thus, the average force exerted on the car is 4850 Newton

Cricetus

The average force exerted on the car during this time will be "4850 N". To understand the calculation, check below.

Force and Mass

According to the question,

Time, t = 5 s

Speed, v = 25 m/s

We know the relation,

→ Acceleration = [tex]\frac{Speed}{Time}[/tex]

By substituting the values,

                         = [tex]\frac{25}{5}[/tex]

                         = 5 m/s²

hence,

→ Force = Mass × Acceleration

             = 970 × 5

             = 4850 N

Thus the above answer is correct.

Find out more information about force here:

https://brainly.com/question/25239010

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