Answer:
The reaction mixture will contain mostly HCN
Explanation:
For weak acids such as HCN with Ka = 7.69 x 10⁻¹⁰ at 25°C
Assume a molar concentration of 0.100M in deionized water ...
[H⁺} = [CN⁻] = √Ka·[Wk Acid] = √(7.69 x 10⁻¹⁰)(0.10) = 8.76 x 10⁻⁶M ...
This is the maximum amount of ions delivered into solution from HCN in aqueous media at 25°C. Such represents a %ionization of only 8.77 x 10⁻³ % at 25°C. Yes, mostly HCN at equilibrium.