A boat travels between two riverside cities, A and B, located 21 miles apart. The river flows in the direction from A to B at 2 mph. The boat takes a total of 10 hours to make a round trip from A to B and back to A again. How long does it take the boat to make the one-way trip from A to B if the boats speed remailer constant relative to the speed of the river in each direction

Respuesta :

Answer:

The time taken by the boat to make the one-way trip from A to B = 3 hrs

Explanation:

Distance between A & B = 21 mile

Velocity of river ( v ) = 2 [tex]\frac{mi}{hr}[/tex]

Total time taken ( T )= 10 hours

[tex]T = \frac{D}{u - v} + \frac{D}{u +v}[/tex]

[tex]10 = \frac{21}{u - 2} + \frac{21}{u + 2}[/tex]

[tex]10 = \frac{42 u}{u^{2}-4 }[/tex]

[tex]10 u^{2} - 42 u -40 = 0[/tex]

[tex]u^{2} - 4.2 u - 4 = 0[/tex]

By solving above equation we get

u = 5 [tex]\frac{mi}{hr}[/tex]

The time taken by the boat to make the one-way trip from A to B

[tex]T = \frac{D}{u + v}[/tex]

[tex]T = \frac{21}{5 + 2}[/tex]

T = 3 hours

This is the time taken by the boat to make the one-way trip from A to B.