Respuesta :
Answer:
The wavelength of the argon laser light is = 5.15 × [tex]10^{-4}[/tex] mm
Explanation:
Separation between slits d = 0.5 mm
Angle [tex]\theta[/tex] = 0.059 °
Order of fringes m = 1
We know that
d [tex]\sin\theta[/tex] = m [tex]\lambda[/tex] ------ (1)
Put all the values in above formula
0.5 ( [tex]\sin0.059[/tex] ) = 1 × [tex]\lambda[/tex]
0.5 × 0.00103 = 1 × [tex]\lambda[/tex]
[tex]\lambda[/tex] = 5.15 × [tex]10^{-4}[/tex] mm
Therefore the wavelength of the argon laser light is = 5.15 × [tex]10^{-4}[/tex] mm
When The maximum of the interference pattern is at an angle of 0.059 degrees of the pattern Therefore The wavelength of the argon laser light is= 5.15 × 10⁻⁴ mm
Calculation of Wavelength of argon laser light
Then Separation between slits d = 0.5 mm
Now, Angle Φ = 0.059 °
After that Order of fringes m = 1
We know that
Then d sinΦ = m ------ (1)
Now Put all the values in above formula
Then 0.5 (sin 0.059 ) = 1 ×λ
After that 0.5 × 0.00103 = 1 × λ
λ = 5.15 × 10⁻⁴mm
Therefore the wavelength of the argon laser light is = 5.15 ×10⁻⁴ mm
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