A pair of power transmission lines each have 2.35-Ω resistance and carry 650 Amp. If the primary voltage of the 10:1 step-up transformer is 3.0 kV, calculate the input voltage of the step-down transformer at the other end.

Respuesta :

Answer:

The input voltage of the step-down transformer is 26.945 kV

Explanation:

Given:

R = 2.35 Ω

I = 650 A

Vs = 10 V

Vp = 1 V

Vs/Vp = 10/1 = 10

Vp = 3 kV

Vs = 10*Vp = 3*10 = 30 kV

The input voltage of the step-down is:

V = Vs - 2IR = 30000 - (2 * 650 * 2.35) = 26945 V = 26.945 kV

The input voltage of the step-down is [tex]26.945kV[/tex]

Transformer:

It is a static device which step up and step down the voltage at same frequency.

Given that,

  • Resistance,[tex]R = 2.35[/tex] Ω
  • Current,[tex]I = 650 A[/tex]
  • Primary voltage, [tex]V_{p} = 1 V[/tex]
  • Secondary voltage , [tex]V_{s}= 10*V_{p} = 3*10 = 30 kV[/tex]

The input voltage of the step-down is,

[tex]V = V_{s} - 2IR = 30000 - (2 * 650 * 2.35) = 26945 V = 26.945 kV[/tex]

Learn more about step up transformer here:

https://brainly.com/question/13597011