Answer:
150mL
Explanation:
First, let us calculate the volume of the diluted solution. This is illustrated below:
Information obtained from the question include:
V1 (initial volume) = 50mL
C1 (initial concentration) = 1M
C2 (final concentration) = 0.25M
V2 (final volume) =.?
The volume of the diluted solution can be obtained using the dilution formula C1V1 = C2V2 as shown below:
C1V1 = C2V2
1 x 50 = 0.25 x V2
Divide both side by 0.25
V2 = 50/0.25
V2 = 200mL
The volume of the diluted solution is 200mL.
Now, to obtain the volume of the water added to the solution, we'll simply subtract the initial volume from the final volume as shown below
Volume of water added = V2 - V1
Volume of water added = 200 - 50
Volume of water added = 150mL
Therefore, the volume of water added is 150mL
The amount, in mL, of water that should be added, will be 150.
According to the dilution equation:
M1V1 = M2V2, where M1 = molarity before dilution, m2 = molarity after dilution, V1 = volume before dilution, and V2 = volume after dilution.
In this case, M1 = 1.0 M, V1 = 50.0 mL, M2 = 0.25 M
Thus: V2 = M1V1/M2 = 1x50/0.25 = 200 mL
This means that 150 mL of water must be added to the 50.0 mL, 1.0 M solution to create a 0.25 M solution.
More on dilution can be found here:https://brainly.com/question/21323871
#SPJ5
