Respuesta :
Answer:
we get the Z-value of given data is [tex]-2.33[/tex].
Yes there is enough evidence to reject the claim.
Step-by-step explanation:
Given that,
Reading speed could be boost to 1050 words per minute.
total number of people is 49.
there average reading speed is 1020 words per minute.
Standard deviation is 90 words per minute.
So, for the Z-value Rounded to nearest Hundredth is
[tex]Z-value = \frac{xbar - u}{\frac{\sigma}{\sqrt{n} } }[/tex]
[tex]xbar = 1020[/tex] [tex]u = 1050[/tex] [tex]n=49[/tex] [tex]\sigma = 90[/tex] putting these values we get,
[tex]z-value = \frac{1020-1050}{\frac{90}{\sqrt{49} } }[/tex]
= [tex]\frac{-30\times 7}{90}[/tex]
= [tex]\frac{-210}{90} =-2.33[/tex]
Here, we get the Z-value of given data is [tex]-2.33[/tex].
Now, for Evidence for Rejecting the claim we need to find P-value
P-value= [tex]P (Z<-2.33)[/tex]
= [tex]0.9903[/tex]
So, Yes there is enough evidence to reject the claim.
