A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company. A survey of 800 randomly selected consumers is to be conducted. For such groups of 800, would it be unusual to get 634 consumers who recognize the Dull Computer Company name?

Respuesta :

Answer:

yes , it would be unusual to get 634 consumers who recognize the Dull Computer Company name .

Step-by-step explanation:

Given  -

A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company.

The probability of success is ( p ) = [tex]68\%[/tex] = .68

The probability of failure  is ( q )  = 1 - p =.32

Sample size (n) = 800

mean [tex]\mathbf{(\nu ) = n\times p}[/tex]

              = [tex]800\times0.68[/tex]

              = 544

Standard deviation [tex](\sigma)[/tex] = [tex]\sqrt{n\times p\times q}[/tex]

                                     =  [tex]\sqrt{544\times .32}[/tex]

                                     = 13.2

Maximum usual values = [tex]\nu + 2s[/tex]

                                      = [tex]544 + 2\times13.2[/tex]

                                      = 570.4

634 is more than 2 standard deviation above the mean, it would be unusual to get 634 consumers who recognize the Dull Computer Company name