Respuesta :
Answer:
Jada is correct.
Step-by-step explanation:
Given equation is as follows,
[tex]-\dfrac{2}{3}\left(x+5\right)+4\left(x+5\right)-\dfrac{10}{3}\left(x+5\right)=0[/tex]
In this case prove that right side of equation is equal to left side of equation.
Now consider left side of the equation,
[tex]-\dfrac{2}{3}\left(x+5\right)+4\left(x+5\right)-\dfrac{10}{3}\left(x+5\right)[/tex]
Factoring out the common term,
[tex]\left(x+5\right)\left(-\dfrac{2}{3}+4-\dfrac{10}{3}\right)[/tex]
Combining the like terms,
[tex]\left(x+5\right)\left(-\dfrac{2}{3}-\dfrac{10}{3}+4\right)[/tex]
Since denominators of first terms are same, so combine the fractions.
[tex]\left(x+5\right)\left(\dfrac{-2-10}{3}+4\right)[/tex]
[tex]\left(x+5\right)\left(\dfrac{-12}{3}+4\right)[/tex]
Divide the number,
[tex]\left(x+5\right)\left(-4+4\right)[/tex]
Subtracting,
[tex]\left(x+5\right)\left(0\right)=0[/tex]
Hence left side of the equation is equal to 0 which is equal to right side of the equation.
Hence Jada saying is correct.
