Answer:
(a) P(next ball with blue) = [tex]\frac{3}{10}[/tex] (b) P(Not to be red) = [tex]1-\frac{2}{5} =\frac{3}{5}[/tex]
(c) P(drawing 70 times yellow ball) = [tex]\frac{1}{10} \times 70 = 7[/tex].
Step-by-step explanation:
Given that,
The total outcomes of the color of tile are :-
Red , Red, Blue, Yellow, Blue, Red, Green, Red, Blue, Green.
From the Question,
Total number of outcomes = 10
(a) What is the probability that her next draw will be blue ?
Red = 4,
Blue = 3,
Green = 2,
Yellow = 1.
P(next ball with blue) = [tex]\frac{3}{10}[/tex].
(b) What is the probability that her next draw will NOT be red?
P(Red ball) = [tex]\frac{4}{10} = \frac{2}{5}[/tex]
But we have to find
P(Not to be red) = [tex]1-\frac{2}{5} =\frac{3}{5}[/tex]
(c) If Amy draws 70 more times with the same tiles from the question above, what probability would you expect a yellow?
P(Yellow ball) = [tex]\frac{1}{10}[/tex]
drawing it 70 times we get the probability
P(drawing 70 times yellow ball) = [tex]\frac{1}{10} \times 70 = 7[/tex].