Answer:
Work done, [tex]W=(0.378i-1.092j)\ J[/tex]
Explanation:
Displacement,
[tex]d=(3i-6.5j)\ mm\\\\d=(0.003i-0.0065j)\ m[/tex]
Force, [tex]F=(126i+168j)\ N[/tex]
Work done by the opponent do on the football player is given by :
[tex]W=F{\cdot} d\\\\W=(126i+168j){\cdot} (0.003i-0.0065j)\ m\\\\W=(0.378i-1.092j)\ J[/tex]
So, the work done by the opponent do on the football player is [tex](0.378i-1.092j)\ J[/tex].
The amount of work done by the opponent on the football player is expressed as [tex](0.378i-1.092j)Joules[/tex]
Work is said to be done if a force applied to an object causes the object to move over a distance.
Given the following parameters
displacement = [tex](3.00 mm)i^ - (6.50 mm)j^[/tex]
Force = [tex]126i+168j[/tex]
Work done = Force * distance
Substitute the given parameters into the formula:
[tex]W=F\times d\\W=(126i+168j)\cdot(3.00i-6.50j)[/tex]
[tex]W=(0.378i-1.092j)Joules[/tex]
Hence the amount of work done by the opponent on the football player is expressed as [tex](0.378i-1.092j)Joules[/tex]
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