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You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 44∘ and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

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calculista

Answer:

The height of the kite is equal to [tex]178.7\ ft[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

The point A is your hand and point C is the kite

we know that

In the right triangle BCD

[tex]sin(44^o)=\frac{CD}{BC}[/tex] ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values

[tex]sin(44^o)=\frac{CD}{250}[/tex]

solve for CD

[tex]CD=sin(44^o)(250)=173.7\ ft[/tex]

The height of the kite is equal to

[tex]AB+CD=5+173.7=178.7\ ft[/tex]

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lpoloyan00001

Answer:

178.7 ft

Step-by-step explanation:

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is $44\degree$  and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

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