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Analyze the graph of a cannonball launched from the ground with an initial velocity of 144 feet per second. The cannonball reached its maximum height after 4.5 seconds.



What was the maximum height the cannonball reached?

feet

Respuesta :

Answer:

324 feet

Step-by-step explanation:

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Considering a quadratic model, the maximum height the cannonball reached was of 324 feet.

What is the model used for a projectile's height?

The generic model is given as follows, considering the height in feet:

[tex]h(t) = -16t^2 + v(0)t + h(0)[/tex]

In which:

  • v(0) is the initial velocity.
  • h(0) is the initial height.

In this problem, it is launched from the ground at a velocity of 144 feet per second, hence h(0) = 0, v(0) = 144, and the model is given by:

[tex]h(t) = -16t^2 + 144t[/tex]

The maximum height was reached after 4.5 seconds, hence:

[tex]h(4.5) = -16(4.5)^2 + 144(4.5) = 324[/tex]

The maximum height the cannonball reached was of 324 feet.

More can be learned about quadratic equations at https://brainly.com/question/24737967

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